SOLUTION: Many states in U.S.A have a lottery game, usually called a Pick-4, in which you pick a fourdigit number such as 7359. During the lottery drawing, there are four bins, each containi

Algebra ->  Probability-and-statistics -> SOLUTION: Many states in U.S.A have a lottery game, usually called a Pick-4, in which you pick a fourdigit number such as 7359. During the lottery drawing, there are four bins, each containi      Log On


   



Question 1167755: Many states in U.S.A have a lottery game, usually called a Pick-4, in which you pick a fourdigit number such as 7359. During the lottery drawing, there are four bins, each containing balls
numbered 0 through 9. One ball is drawn from each bin to form the four-digit winning number.
a. You purchase one ticket with one four-digit number. What is the probability that you will
win this lottery game?
b. There are many variations of this game. The primary variation allows you to win if the four
digits in your number are selected in any order as long as they are the same four digits as
obtained by the lottery agency. For example, if you pick four digits making the number
1265, then you will win if 1265, 2615, 5216, 6521, and so forth, are drawn. The variations
of the lottery game depend on how many unique digits are in your number. Consider the
following four different versions of this game. Find the probability that you will win this
lottery in each of these four situations.
i. All four digits are unique (e.g., 1234)
ii. Exactly one of the digits appears twice (e.g., 1223 or 9095)
iii. Two digits each appear twice (e.g., 2121 or 5588)

Answer by ikleyn(52790) About Me  (Show Source):
You can put this solution on YOUR website!
.

For part (a), I just answered under this link

https://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.1167754.html

https://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.1167754.html


(b, i)  In this case, you consider COMBINATIONS of 10 digits taken 4 at a time.


        There are  C%5B10%5D%5E4 = %2810%2A9%2A8%2A7%29%2F%281%2A2%2A3%2A4%29 = 210  such combinations, in all.


        Of them, only one is winning.


        Therefore, the probability to win is  1%2F210  in this case.

Solved.

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