SOLUTION: how many grams of sugar must be added to 60 grams of a solution that is 32% sugar to obtain a solution that is 50% sugar?
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: how many grams of sugar must be added to 60 grams of a solution that is 32% sugar to obtain a solution that is 50% sugar? This question is from textbook algerba1
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A typical mixture problem, learn this method and you can do most of them easily
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Let x = amt of pure sugar required, the decimal amt of pure sugar 1.0(x)
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We know the resulting amt = (x+60)
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A simple equation:
.32(60) + 1.0(x) = .50(x+60)
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19.2 + x = .5x + 30
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x - .5x = 30 - 19.2
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.5x = 10.8
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x = 10.8/.5
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x = 21.6 grams of pure sugar required
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We can check our solution by substitution in our original equation:
.32(60) + 21.6 = .5(21.6+60)
19.2 + 21.6 = .5(81.6)
40.8 = 40.8
