SOLUTION: quien me ayuda por favor. Si 𝑃(𝐴1) = 0.40, 𝑃(𝐴2) = 0.28, 𝑃(𝐴3) = 0.32, 𝑃(𝐵1/𝐴1) = 0.08, 𝑃(𝐵1/𝐴2) = 0.03, 𝑃(𝐵1/𝐴3) = 0.12, obtenga

Algebra ->  Probability-and-statistics -> SOLUTION: quien me ayuda por favor. Si 𝑃(𝐴1) = 0.40, 𝑃(𝐴2) = 0.28, 𝑃(𝐴3) = 0.32, 𝑃(𝐵1/𝐴1) = 0.08, 𝑃(𝐵1/𝐴2) = 0.03, 𝑃(𝐵1/𝐴3) = 0.12, obtenga       Log On


   

Question 1167581: quien me ayuda por favor.
Si 𝑃(𝐴1) = 0.40, 𝑃(𝐴2) = 0.28, 𝑃(𝐴3) = 0.32, 𝑃(𝐵1/𝐴1) = 0.08,
𝑃(𝐵1/𝐴2) = 0.03, 𝑃(𝐵1/𝐴3) = 0.12, obtenga 𝑃(𝐴2/𝐵1).
Answer by ikleyn(52895) About Me  (Show Source):
You can put this solution on YOUR website!
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As the problem is presented in the post,  it is incomplete and,   T H E R E F O R E ,   can  NOT  be solved.



In order for the problem formulation be complete,  it  MUST  say that the events  A1,  A2  and  A3

are  DISJOPINT  (or  MUTUALLY  EXCLUSIVE,  which is  EQUIVALENT).