With the like factors of (x+1) in both numerator and denominator, there will be a hole in the graph at x=-1; everywhere else the graph will be the same as the graph of
The original inequality is true whenever x is less than or equal to 3, except that it is undefined at x=-1.
ANSWER: (-infinity, -1) union (-1,3]
Here is a graph of the given function; it won't show the hole in the graph at (-1,-4):
A graphing utility like a TI-83 calculator will show the hole if an appropriate viewing window is used.