Question 1167536: On a wall 63 1/2 cm wide, Peter is going to hang two pictures beside each other, each measuring 15 1/3 cm wide. He will leave 10 2/5 cm in between the pictures. He plans to use two nails to hang each picture, and will centre these nails leaving 10 1/4 cm between each pair. How far, in cm, from the end of the wall (on either side) will the first nail be placed?
Answer by greenestamps(13195)   (Show Source):
You can put this solution on YOUR website!
Draw a picture of the wall. Note that since the arrangement on the wall is symmetrical, you really only need a picture of half of the wall.
To find how far from the wall the nail closest to the wall will be....
(1) start at the middle of the wall;
(2) move towards the wall a distance equal to half the distance between the two pictures;
(3) move farther towards the wall the width of each picture; and
(4) move AWAY from the wall half the difference between the width of the picture and the distance between the two nails for each picture (if you have drawn the picture correctly, that should make sense).
The calculations (ugly fractions that will need common denominators)...
(1) half of 63 1/2...
(2) minus half of 10 2/5...
(3) minus 15 1/3...
(4) plus half of (15 1/3 - 10 2/5)
You can have the pleasure of doing all those calculations....
|
|
|
