Question 1167123: Find an equation of the line perpendicular to the line y= 5/2 x - 3/14 and contains the point ( 10, 8 ) .
Answer by math_helper(2461)   (Show Source):
You can put this solution on YOUR website! Remember these two things:
Given line A...
1. If line B is perpendicular to line A, slopeB = - 1/slopeA
2. y - y0 = m(x-x0) where m=slope and (x0,y0) is a point on the line, is the point-slope form of the equation of a line.
Armed with the above two facts, you can write the perpendicular line equation by inspection:
y - 8 = (-2/5)(x - 10)
Alternatively, the above can be re-arranged:
Slope-intercept form y=mx+b: y = (-2/5)x + 12
Standard form Ax + By = C: (2/5)x + y = 12
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