Question 1167100: Not sure whether I placed this question in the correct category-
Hello, could you help me with this problem I appreciate it much so.
Question:
What is the maximum length that is acceptable if a tolerance of 0.005 inches is permitted on a piece designed to be 1.625 inches?
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I computed it and came up with and answer of 1.63 inches but not sure whether I need to round the number because of its precision. I just need an expert Math Tutor to verify whether this is correct.
Thank You all Math Tutors!
Sammy
US Navy Veteran
Found 2 solutions by Theo, solver91311:
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! i believe your answer of 1.63 is good.
i don't believe you would want to round your answer, since your measurement needs to be exact.
if the length of the piece is 1.625 and the tolerance is plus or minus .005, then the length of the piece could be as little as 1.625 minus .005 and as much as 1.625 plus .005.
that would mean that the length of the piece is acceptable if it is anywhere between 1.62 and 1.63.
you would not want to round it to anything less than the value shown.
you do normally show the trailing zeroes in the decimal part of the answer unless there is a requirement to do so.
Answer by solver91311(24713)  (Show Source):
You can put this solution on YOUR website!
I'm presuming the specification is  inches.
So the measurement is given to three decimal place precision, so anything that has to do with it has to be specified to three decimal place precision. Consequently, your answer to the question is incorrect. The answer is  .
What's the difference? A lot. is ten times more precise than  . To put it in a slightly different context, let's say I told you that I had taken a measurement and it was  inch. What am I saying? When I make that claim, I am only guaranteeing that the actual measurement is in the range  . But if I were to make the claim that the measurement was  inch, I would be guaranteeing that the measurement is in the range 
So, and the other end is 
John
FCCS(SW), USN, Ret.
My calculator said it, I believe it, that settles it
I > Ø
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