SOLUTION: find four consecutive odd intergers such that 6 times the sum of the first and third is 3 more than 5 times the opposite of the fourth. 6(x+x+4)=3-5(x+6)

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: find four consecutive odd intergers such that 6 times the sum of the first and third is 3 more than 5 times the opposite of the fourth. 6(x+x+4)=3-5(x+6)      Log On


   

Question 1167058: find four consecutive odd intergers such that 6 times the sum of the first and third is 3 more than 5 times the opposite of the fourth.

6(x+x+4)=3-5(x+6)
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
--------------------------------------------------
four consecutive odd integers such that 6 times the sum of the first and third is 3 more than 5 times the opposite of the fourth.
-----------------------------------------------------
system%28Integers%2Cn%2Cn%2B2%2Cn%2B4%2Cn%2B6%29

6%28n%2Bn%2B4%29=5%28-n-6%29%2B3-------equivalent to yours, so all you need is do the arithmetic.

RESULT: -3, -1, 1, 3