SOLUTION: P is a point (7, 5) and l1 is the line with equation 3x + 4y = 16.
a) Find the equation of the line l2 which passes through P and is perpendicular to l1.
b) Find the point of int
Algebra ->
Coordinate-system
-> SOLUTION: P is a point (7, 5) and l1 is the line with equation 3x + 4y = 16.
a) Find the equation of the line l2 which passes through P and is perpendicular to l1.
b) Find the point of int
Log On
Question 1167027: P is a point (7, 5) and l1 is the line with equation 3x + 4y = 16.
a) Find the equation of the line l2 which passes through P and is perpendicular to l1.
b) Find the point of intersection of the lines l1 and l2 and find the perpendicular distance of P from the
line l1. Found 2 solutions by josgarithmetic, Alan3354:Answer by josgarithmetic(39620) (Show Source):
You can put this solution on YOUR website! A similar problem:
-------
P is a point (2,3) and L1 is the line with equation 3x + 2y = 11.
a) Find the equation of the line L2 which passes through P and is perpendicular to L1.
---
Find the slope, m1, of L1.
3x + 2y = 11
Solve for y
y = (-3/2)x - 11/2
m1 = -3/2
---------
The slope of lines perpendicular to L1 is the negative inverse, m2 = 2/3
-----
y-y1 = m2*(x-x1) where (x1,y1) = (2,3)
y-3 = (2/3)*(x-2)
==========================
b) Find the point of intersection of the lines L1 and L2
y-3 = (2/3)*(x-2)
3y-9 = 2x-4
2x - 3y = -5
3x + 2y = 11
-------
4x - 6y = -10
9x + 6y = 33
--------------------- Add
13x = 23
x = 23/13
y = (2x/3) - 4/3 + 3 = 46/39 - 52/39 + 117/39 = 37/13
------
Intersection is (23/13,37/13)
======================
and find the perpendicular distance of P from the
line L1.