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Let x be the middle of the three consecutive even integers.
Then (x-2) and (x+2) are two other "extreme" integers.
The equation, from the condition, is
(x-2)*(x+2) = 3x, or
x^2 - 4 = 3x
x^2 - 3x - 4 = 0
Factor left side
(x-4)*(x+1) = 0.
Of the two roots x= 4 and x= -1, only x= 4 satisfies the condition to be even integer number.
ANSWER. The numbers are 2, 4 and 6.
Solved.