Question 1166771: The local theater has three types of seats for Broadway plays: main floor, balcony, and mezzanine. Main floor tickets are $57, balcony tickets are $51, and mezzanine tickets are $49. One particular night, sales totaled $89,213. There were 51 more main floor tickets sold than balcony and mezzanine tickets combined. The number of balcony tickets sold is 337 more than 2 times the number of mezzanine tickets sold. How many of each type of ticket were sold?
Answer by greenestamps(13203)   (Show Source):
You can put this solution on YOUR website!
Take the time to read and digest the given information so you can set up the problem using a single variable:
x = # of mezzanine tickets
2x+337 = # of balcony tickets (337 more than two times the number of mezzanine tickets)
(x)+(2x+337)+51 = 3x+388 = # of main floor tickets sold (51 more than balcony and mezzanine tickets combined)
Then use those expressions, and the prices for each kind of ticket, to write and solve the equation that says the total ticket sales were $89,213.
Solve using basic algebra... although the numbers are "ugly", so it will take some time.
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