SOLUTION: Laura is bowling 5 games. Her first 4 scores were 144, 86, 124, and 118. To end up with an average score of at least 125, what is the lowest score Laura will need in the fifth g

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: Laura is bowling 5 games. Her first 4 scores were 144, 86, 124, and 118. To end up with an average score of at least 125, what is the lowest score Laura will need in the fifth g      Log On


   



Question 1166368: Laura is bowling 5 games. Her first 4 scores were 144, 86, 124, and 118.
To end up with an average score of at least 125, what is the lowest score Laura will need in the fifth game?

Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52785) About Me  (Show Source):
You can put this solution on YOUR website!
.

To answer the question, you need solve this inequality


    %28144+%2B+86+%2B+124+%2B+118+%2B+x%29%2F5 >= 125.


Simplify and find x


    472 + x >= 125*5

   x >= 125*5 - 472 = 153.


ANSWER.  The lowest score Laura will need in the fifth game is 153.

Solved.

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Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


The other tutor showed a standard method for solving the problem -- by adding the given scores and calculating the score required to get the desired average.

Here is another way to solve a problem like this, in which a particular average needs to be obtained.

This method is not any easier than the standard method in this particular problem, because the given scores aren't very "close together". But the method can be much easier if the numbers are large numbers that are close together.

To use this method, compare each score to the desired average and determine the "over" and "under" for each score. Then the score needed in the next game is the score that balances the "over" and "under".

144: +19
86: -39
124: -1
118: -7

Total after four games: 19-39-1-7 = -28

Minimum score required to get an average of 125: 125+28 = 153