SOLUTION: GIVE WHAT IS ASKED IN THE PROBLEM. SHOW YOUR COMPLETE SOLUTION: LINDA STARTS A CHAIN LETTER AND SENDS IT TO THREE FRIENDS. EACH OF THE FRIENDS SENDS THE LETTER TO 3 OTHER FRIEND

Algebra ->  Sequences-and-series -> SOLUTION: GIVE WHAT IS ASKED IN THE PROBLEM. SHOW YOUR COMPLETE SOLUTION: LINDA STARTS A CHAIN LETTER AND SENDS IT TO THREE FRIENDS. EACH OF THE FRIENDS SENDS THE LETTER TO 3 OTHER FRIEND      Log On


   



Question 1166362: GIVE WHAT IS ASKED IN THE PROBLEM. SHOW YOUR COMPLETE SOLUTION:
LINDA STARTS A CHAIN LETTER AND SENDS IT TO THREE FRIENDS. EACH OF THE FRIENDS SENDS THE LETTER TO 3 OTHER FRIENDS AND THE SEQUENCE IS REPEATED. ASSUMING THAT NO ONE BREAKS THE CHAIN, HOW MANY LETTERS WILL HAVE BEEN SENT FROM THE FIRST TO THE SIXTH MAILINGS?

Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
.


            I just answered this question once,  but it came again.
            Ok,  I will explain one more time.


Mailing               1    2    3    4    5    6

number of letters     1    3    3^2  3^3  3^4  3^5
   sent


The total = 1 + 3 + 3^2 + 3^3 + 3^4 + 3^5.


Use your calculator.


Or, alternatively,  use the formula for the sum of the first 6 terms of an geometric progression 
with the first term of 1 and the common ratio of 3.

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To learn the formula for summing, see introductory lessons on geometric progressions
    - Geometric progressions
    - The proofs of the formulas for geometric progressions
    - Problems on geometric progressions
    - Word problems on geometric progressions
in this site.

Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic
"Geometric progressions".

Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.


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