SOLUTION: Please help me solve this problem log2(2x) - log2(x + 1) = -3

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Please help me solve this problem log2(2x) - log2(x + 1) = -3       Log On


   

Question 1166261: Please help me solve this problem log2(2x) - log2(x + 1) = -3
Found 2 solutions by solver91311, math_helper:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!




The difference of the logs is the log of the quotient



The definition of the logarithm function is:



So





Solve for

John

My calculator said it, I believe it, that settles it


I > Ø

Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
+log%282%2C%282x%29%29+-+log%282%2C%28x%2B1%29%29+=+-3+
+log%282%2C+%282x%2F%28x%2B1%29%29%29+=+-3+ (b/c log(a/b) = log(a)-log(b))
++2x%2F%28x%2B1%29+=+2%5E%28-3%29+=+1%2F8+

++16x%2F%28x%2B1%29+=+1+

+highlight%28+x+=+1%2F15+%29+