SOLUTION: Joan has one solution that is 18% acid and a second solution that is 43% acid how many liters of each should she mix together in order to get an 80 liters solutions that is 26.5% a
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-> SOLUTION: Joan has one solution that is 18% acid and a second solution that is 43% acid how many liters of each should she mix together in order to get an 80 liters solutions that is 26.5% a
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Question 1166227: Joan has one solution that is 18% acid and a second solution that is 43% acid how many liters of each should she mix together in order to get an 80 liters solutions that is 26.5% acid Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website! let x equal the number of liters of the first solution.
let y equal the number of liters of the second solution.
you have 2 equations that need to be solved simultaneously.
they are:
x + y = 80
.18 * x + .43 * y = .265 * 80
multiply both sides of the first equation by .18 and simplify both equations to get:
.18 * x + .18 * y = 14.4
.18 * x + .43 * y = 21.2
subtract the first equation from the second to get:
.25 * y = 6.8
solve for y to get:
y = 6.8 / .25 = 27.2
since x + y = 80, then x must be equal to 80 - 27.2 = 52.8.
you have x = 52.8 and y = 27.2
x + y = 52.8 + 27.2 = 80 which is correct.
.18 * x + .43 * y = .18 * 52.8 + .43 * 27.2 = 21.2 which is correct.
21.2 / 80 = .265 = 26.5% which is also correct.
the solution is confirmed to be good.
your solution is that she needs to mix 52.8 liters of the 18% solution and 27.2 liters of the 43% solution to get a solution that an 80 liter solution that is 26.5% acid.
