Question 116621: Susan has red, blue, green, and yellow sweaters. Joanne has green, red, purple, and white sweaters. Diane's sweaters are red, blue, purple, and mauve. Each girl has only one sweater of each color, and will pick a sweater to wear at random. Find the probabiltiy of each question!!!!
P(each girl chooses a different color)
P(each girl chooses the same color)
P(two girls choose the same color, and the third chooses a different color)
Thank you-Jasmine
Answer by edjones(8007)   (Show Source):
You can put this solution on YOUR website! Write a group of 3 rows for girl names and and 7 columns for colors
Each girl chooses the same color (easiest)
The only color they can choose is red.
(1/4)^3=1/64
.
P(two girls choose the same color, and the third chooses a different color)
For Susan chooses red & another picks red: 2(1/4 * 1/4 * 3/4) =============6/64
For Susan chooses red & and both others pick purple: 1/4 * 1/4 * 1/4=======1/64
For Susan chooses blue & Diane picks blue: 1/4 * 1/4 * 4/4=================4/64
For Susan chooses blue & and both others pick purple or red:1/4*2/4*1/4====2/64
For Susan chooses green & Joanne picks green: 1/4 * 1/4 * 4/4==============4/64
For Susan chooses green & and both others pick purple or red:1/4*2/4*1/4===2/64
For Susan chooses yellow & and both others pick purple or red:1/4*2/4*1/4==2/64
Total: 21/64
.
For each chosing a different color.
1-22/64=42/64=21/32
.
Ed
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