SOLUTION: The length of a rectangle is two less than half the width. Four times the length is eight less than twice the perimeter. Find the dimensions.

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Question 1166080: The length of a rectangle is two less than half the width. Four times the length is eight less than twice the perimeter. Find the dimensions.
Answer by josgarithmetic(39631) About Me  (Show Source):
You can put this solution on YOUR website!
L, length
w, width

First sentence, L=w%2F2-2

Second sentence, 4L=2%28L%2Bw%29-8

Maybe you can do the rest on your own.


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First Sentence equation 2L=w-4
2L-w=-4

Second Sentence equation 4L=2L%2B2w-8
3L=2w-8
3L-2w=-8

Revised System: system%282L-w=-4%2C3L-2w=-8%29
One way to go from here, is multiply first equation by 2, and subtract the "first" from "second".

system%284L-2w=-8%2C3L-2w=-8%29
L=0-----------------------makes no sense.

-----rechecking------

Problem as given is wrong. No Solution!


-----REDO-----------------
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system%28L=w%2F2-2%2C4L=2%28L%2Bw%29-8%29
.
.
.
system%28w-2L=4%2Cw-L=4%29-----------impossible.......NO SOLUTION