SOLUTION: a committee of three people is selected at random from a sec system of six teachers, four parents of students, and seven alumni. A) What is the probability of the event that the c

Algebra ->  Probability-and-statistics -> SOLUTION: a committee of three people is selected at random from a sec system of six teachers, four parents of students, and seven alumni. A) What is the probability of the event that the c      Log On


   



Question 1166019: a committee of three people is selected at random from a sec system of six teachers, four parents of students, and seven alumni.
A) What is the probability of the event that the committee consists of all teachers?
B) What is the probability of the event that the committee has no teachers?

Found 2 solutions by Boreal, ikleyn:
Answer by Boreal(15235) About Me  (Show Source):
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the denominator is the number of ways to choose 3 from 20, which is 1140
all teachers is 6C3 4P0 7A0 which is 20/1140 or 0.0175
no teachers is 6C0*11C3/20C3
this is 165/1140 or 0.1447

Answer by ikleyn(52810) About Me  (Show Source):
You can put this solution on YOUR website!
.

the denominator is the number of ways to choose 3 from (6+4+7) = 17, which is  C%5B17%5D%5E3 = %2817%2A16%2A15%29%2F%281%2A2%2A3%29 = 680.


all teachers is  C%5B6%5D%5E3 = %286%2A5%2A4%29%2F%281%2A2%2A3%29 = 20 ways.


So the answer to (a) is  P = 20%2F680 = 0.029412.




no teachers is  C%5B4%2B7%5D%5E3 = C%5B11%5D%5E3 = %2811%2A10%2A9%29%2F%281%2A2%2A3%29 = 165 ways.


So the answer to (b) is  P = 165%2F680 = 0.242647.