SOLUTION: An arithmetic sequence starts 23, 36, 49, 62, …. What is the first term of the sequence to exceed 200,000?
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Question 1165705: An arithmetic sequence starts 23, 36, 49, 62, …. What is the first term of the sequence to exceed 200,000? Answer by ikleyn(52788) (Show Source):
First term of the AP is 23; the common difference is 13.
You want to find the minimal integer "n" such that
23 + 13*(n-1) >= 200000.
Then n-1 >= = 15382.85; hence, n = 15383 + 1 = 15384. ANSWERCHECK. 23 + 13*(15384-1) = 200002. ! Ok !
