SOLUTION: They each were riding their bikes from their homes. Jose lives 10 miles away. Josh lives 15 miles away. Jess lives 12 miles away. Jake lives 9 miles away. They want to be at the pa
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: They each were riding their bikes from their homes. Jose lives 10 miles away. Josh lives 15 miles away. Jess lives 12 miles away. Jake lives 9 miles away. They want to be at the pa
Log On
Question 1165399: They each were riding their bikes from their homes. Jose lives 10 miles away. Josh lives 15 miles away. Jess lives 12 miles away. Jake lives 9 miles away. They want to be at the park by 1:15. if they each ride at 15 miles per hour what time should the first person leave to meet their friend on time Found 2 solutions by ikleyn, MathTherapy:Answer by ikleyn(52810) (Show Source):
The person who lives at the maximum distance, requires maximum time.
It is Josh, who lives 15 miles away.
He needs 1 hour travel time; hence, he should start first at 12:15.
You can put this solution on YOUR website!
They each were riding their bikes from their homes. Jose lives 10 miles away. Josh lives 15 miles away. Jess lives 12 miles away. Jake lives 9 miles away. They want to be at the park by 1:15. if they each ride at 15 miles per hour what time should the first person leave to meet their friend on time
Depends on who the 1st person you're referring to is!
The 1st person in the problem is Jose. Are you talking about him?
If you're referring to the person who lives farthest away from the park, then that's Josh!