| 
 
 
| Question 1165278:  You invested $29,000 in two accounts paying 6% and 8% annual interest, respectively. If the total interest earned for the year was $ 2300,how much was invested at each rate?
 Answer by Seutip(231)
      (Show Source): 
You can put this solution on YOUR website! Let x be the amount invested at 6% y be the amount invested at 8%
 Equations:
 x+y=29,000
 0.06x+0.08y=2300
 So, x=29,000-y the substitue
 0.06(29,000-y)+0.08y=2300
 1740-0.06y+0.08y=2300
 0.02y=560
 y=28,000
 x=1,000
 You invested $1000 in 6% and $28000 in 8%
 Hope that helps!
 | 
  
 | 
 |