SOLUTION: If the sides of a square are decreased by 2 cm, the area is decreased by 36 cm^2. What were the dimensions of the original square? huh?

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: If the sides of a square are decreased by 2 cm, the area is decreased by 36 cm^2. What were the dimensions of the original square? huh?      Log On


   



Question 116522: If the sides of a square are decreased by 2 cm, the area is decreased by
36 cm^2. What were the dimensions of the original square? huh?

Found 2 solutions by josmiceli, solver91311:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = the original sides of the square
Let A = the original area of the square
A+=+x%5E2
A+-+36+=+%28x+-+2%29%5E2
A+-+36+=+x%5E2+-+4x+%2B+4
x%5E2+-+36+=+x%5E2+-+4x+%2B+4
-36+=+-4x+%2B+4
4x+=+36+%2B+4
x+=+10cm answer
The original square was 10 cm X 10 cm
check answer
A+-+36+=+%28x+-+2%29%5E2
A+-+36+=+%2810+-+2%29%5E2
A+-+36+=+64
A+=+100
If I decrease A by 36, I get 64 cm2, and that's
an 8 X 8 square or (10-2) X (10-2)

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
Start with defining a variable to represent the length of a side of the original square, let's call it x.
So the area of the original square would be A%5Bo%5D=x%5E2.

The new square is 2 cm shorter on each side, so one of the sides must measure x-2, and the area of the new square must be A%5Bn%5D=%28x-2%29%5E2.

But we know that A%5Bo%5D=A%5Bn%5D%2B36cm%5E2. Substituting: x%5E2=%28x-2%29%5E2%2B36.

Now, expand the binomial, collect terms, and put the equation in standard form.

x%5E2=x%5E2-4x%2B4%2B36
x%5E2-x%5E2=x%5E2-x%5E2-4x%2B40
-4x%2B40=0
-4x=-40
x=10

So the original square was 10 cm on a side.

Let's check the answer.

Original area 10%5E2=100
New area 8%5E2=64
100-64=36, Check.