SOLUTION: At the city museum, child admission is $5.30 and adult admission is $8.90. On Saturday, three times as many adult tickets as child tickets were sold, for a total sales of $800.00.
Algebra ->
Customizable Word Problem Solvers
-> Numbers
-> SOLUTION: At the city museum, child admission is $5.30 and adult admission is $8.90. On Saturday, three times as many adult tickets as child tickets were sold, for a total sales of $800.00.
Log On
Question 1165074: At the city museum, child admission is $5.30 and adult admission is $8.90. On Saturday, three times as many adult tickets as child tickets were sold, for a total sales of $800.00. How many child tickets were sold that day? Answer by greenestamps(13195) (Show Source):
Group all the tickets sold into groups of 3 adult tickets and one child ticket. The cost of each such group of tickets is 3($8.90)+$5.30 = $26.70+$5.30 = $32.
The number of those groups of tickets that need to be sold to make $800 is 800/32 = 25.
Then, since each group consists of 3 adult tickets and one child ticket, the number of child tickets sold was 25.
For a formal algebraic setup....
x = # of child tickets at $5.30 each
3x = # of adult tickets at $8.90 each
