SOLUTION: Use two equations in two variables to solve the application. See Example 4. (Objective 1)
Peter invested some money at 6% annual interest, and Martha invested some at 12%. If th
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-> SOLUTION: Use two equations in two variables to solve the application. See Example 4. (Objective 1)
Peter invested some money at 6% annual interest, and Martha invested some at 12%. If th
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Question 1164915: Use two equations in two variables to solve the application. See Example 4. (Objective 1)
Peter invested some money at 6% annual interest, and Martha invested some at 12%. If their combined investment was $6,000 and their combined interest was $510, how much money did Martha invest?
$
You can put this solution on YOUR website! x+y=6000. x is at 6%, y is at 12%
.06x+.12y=510
6x+12y=51000
-6x-6y=-36000, multiplying the top by -6
6y=15000
y=$2500 @ 12% =$300
x=$3500 @ 6%=$210
