SOLUTION: Find two consecutive integers of whose product of 72

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Find two consecutive integers of whose product of 72      Log On


   

Question 1164418: Find two consecutive integers of whose product of 72
Found 2 solutions by Theo, Alan3354:
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
let x = the number.
x * (x + 1) = 72
simplify to get:
x^2 + x = 72
subtract 72 from both sides of the equation to get:
x^2 + x - 72 = 0
factor the equation to get:
(x + 9) * (x - 8) = 0
solve for x to get:
x = -9 or x = 8
if x = 8, then 8 * 9 = 72
if x = -9, then -9 * -8 = 72
your answer will be either 8 and 9 or -9 and -8.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find two consecutive integers of whose product of 72
----
sqrt%2872%29+=+8.485
---> 8 & 9 or -9 & -8