You can
put this solution on YOUR website! Determine the required value of the missing probability to make the
distribution a discrete probability distribution.
x P(x)
3 0.33
4 ?
5 0.23
6 0.17
--------------------------------
The probabilities have to add up to 1. Put an N for the question mark:
x P(x)
3 0.33
4 N
5 0.23
6 0.17
Add 'em up, and set it equal to 1:
0.33 + N + 0.23 + 0.17 = 1
N + 0.73 = 1
N = 1 - 0.73
N = 0.27
x P(x)
3 0.33
4 0.27
5 0.23
6 0.17
Now it's a discrete probability distribution.
That's all there is to it!
Edwin