Question 1164078: solve the quadratic equations by extarcting[sic] or by factoring method whichever is applicable.
1. x² = 25 (space) : x = (blank) , x = (blank)
2. ( x + 1 ) ( x - 2 ) (space) : x = (blank) , x = (blank)
3. x² + 3x = 0 (space) : x = (blank) , x =(blank)
4. ( x - 4 )² (space) : x = (blank) , x =(blank)
5. ( x - 3 ) ( 2x - 5 ) (space) : x = (blank) , x =(blank)
Found 2 solutions by josgarithmetic, Alan3354:
Answer by josgarithmetic(39630)   (Show Source):
You can put this solution on YOUR website! ----------------------------------------
solve the quadratic equations by extarcting or by factoring method whichever is applicable.
1. x² = 25 (space) : x = (blank) , x = (blank)
2. ( x + 1 ) ( x - 2 ) (space) : x = (blank) , x = (blank)
3. x² + 3x = 0 (space) : x = (blank) , x =(blank)
4. ( x - 4 )² (space) : x = (blank) , x =(blank)
5. ( x - 3 ) ( 2x - 5 ) (space) : x = (blank) , x =(blank)
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Attempting only #4 the way you may mean it,
Already a factored EXPRESSION. It is not any equation.
Attempting #3, an actual equation,
Roots should be obvious.
Factoring, have  ,
and roots seen are 0 and -3.
Answer by Alan3354(69443)  (Show Source):
You can put this solution on YOUR website! solve the quadratic equations by extarcting [sic] or by factoring method whichever is applicable.
1. x² = 25 (space) : x = (blank) , x = (blank)
2. ( x + 1 ) ( x - 2 ) (space) : x = (blank) , x = (blank)
3. x² + 3x = 0 (space) : x = (blank) , x =(blank)
4. ( x - 4 )² (space) : x = (blank) , x =(blank)
5. ( x - 3 ) ( 2x - 5 ) (space) : x = (blank) , x =(blank)
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The quadratic equation method is always applicable.
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(space) and "x = (blank)" are not needed, and are just irritating.
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#1 and #3 are equations, each has an equal sign.
The others are not equations.
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