SOLUTION: 2 pipes fill up a pool. When both are used to fill water, it takes 1.2 hours to fill up the pool. If one is intake pipe and one is drainage pipe, it takes 6 hours to fill up the po

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: 2 pipes fill up a pool. When both are used to fill water, it takes 1.2 hours to fill up the pool. If one is intake pipe and one is drainage pipe, it takes 6 hours to fill up the po      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1163899: 2 pipes fill up a pool. When both are used to fill water, it takes 1.2 hours to fill up the pool. If one is intake pipe and one is drainage pipe, it takes 6 hours to fill up the pool. How long does each pipe alone need to fill up?
Answer by ikleyn(52790) About Me  (Show Source):
You can put this solution on YOUR website!
2 pipes fill up a pool. When bot are used to fill water, it takes 1.2 hours to fill up the pool.
If one is intake pipe and one is drainage pipe, it takes 6 hours to fill up the pool. How long does each pipe alone need to fill up?
~~~~~~~~~~`


Let x be the rate of the first pipe and y be the rate of the second pipe.


    Notice that from the context, for each pipe, the rate filling is the same as the rate draining.


From the first condition,  the combined rate    x + y  is  1%2F1.2 = 10%2F12 = 5%2F6  of the pool volume per hour.

From the second condition, the net inflow rate  x - y  is  1%2F6  of the pool volume per hour.


So you have this system of 2 equations

    x + y = 5%2F6    (1)

    x - y = 1%2F6.   (2)


Add the equations and get  2x = 1,  x = 1%2F2.


So, first pipe fills the pool in 2 hours, working alone.


Next, from equation (1)  

    y = 5%2F6 - x = 5%2F6 - 1%2F2 = 5%2F6+-+3%2F6 = 2%2F6 = 1%2F3.


Hence, the second pipe fills the pool in 3 hours, working alone.

Solved.