SOLUTION: Solve the equation for 0 <= θ < 2 pi. What is -6 sin θ = 3 square root of 3.

Algebra ->  Trigonometry-basics -> SOLUTION: Solve the equation for 0 <= θ < 2 pi. What is -6 sin θ = 3 square root of 3.       Log On


   

Question 1163783: Solve the equation for 0 <= θ < 2 pi. What is -6 sin θ = 3 square root of 3.
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
 0 <= θ < 2 pi. What is -6 sin θ = 3 square root of 3.

-6sin%28theta%29%22%22=%22%223sqrt%283%29

Divide both sides by -6

sin%28theta%29%22%22=%22%223sqrt%283%29%2F%28-6%29

sin%28theta%29%22%22=%22%22-sqrt%283%29%2F2

The sine is positive only in QIII and QIV

theta%22%22=%22%224pi%2F3ortheta%22%22=%22%225pi%2F3

Edwin