Question 1163701: johny has a coin collection. he has 9898 coins in all. he has 33 times as many pennies as dimes. he has 44 more dimes than nickles, and 66 less dimes than quarters. how many of each coin does he have
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52863)   (Show Source):
Answer by greenestamps(13203)  (Show Source):
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johny has a coin collection. he has  98 coins in all. he has  3 times as many pennies as dimes. he has  4 more dimes than nickles, and  6 less dimes than quarters.
Read the given information and take a bit of time to find a way to write expressions for the numbers of pennies, nickels, dimes, and quarters as easily as possible using a single variable.
The number of pennies is 3 times the number of dimes: x = number of dimes; 3x = number of pennies.
He has 4 more dimes than nickels, so the number of nickels is 4 less than the number of dimes: x-4 = number of nickels.
He has 6 fewer dimes than quarters, so the number of quarters is 6 more than the number of dimes: x+6 = number of quarters.
Now that you have expressions in terms of a single variable for the numbers of each coin, write and solve the equation that says the total number of coins is 98:
I'll let you finish from there....
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