SOLUTION: Ref. Question 1163498: Volume of coins; Penny; .0213 cu. in. Nickel; .0438 " " Dime; .0012 " " Quarter; .000049 " " Half Dollar; .097 " " Maybe that will be of

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Ref. Question 1163498: Volume of coins; Penny; .0213 cu. in. Nickel; .0438 " " Dime; .0012 " " Quarter; .000049 " " Half Dollar; .097 " " Maybe that will be of      Log On

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Question 1163505: Ref. Question 1163498:
Volume of coins;
Penny; .0213 cu. in.
Nickel; .0438 " "
Dime; .0012 " "
Quarter; .000049 " "
Half Dollar; .097 " "
Maybe that will be of assistance.

Answer by ikleyn(52880) About Me  (Show Source):
You can put this solution on YOUR website!
.

It does not assist,  since the total volume of coins  IS  NOT  GIVEN.

The given is the volume of the bucket,  which is  TOTALLY  DIFFERENT  THING.



Hello,  why you want to solve the problem,  which is formulated  IMPROPERLY ?

For what ?   What is your goal ?   What do you want to learn from it ?


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What you can do, is to ESTIMATE the maximum number of coins of each type by dividing the total given volume
by the volume of each separate type of coins, assuming that the content is homogeneous.

But not to determine the number of different type of coins in the mixture.


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Also, in your post I see these numbers (in cubic inches)
Nickel; .0438 " "
Dime; .0012 " "
Quarter; .000049 " "  

When I compare the volumes of dimes and quarters in your table, I can not believe that these numbers are correct.