SOLUTION: without computing each sum find which is greater o or e and by how much o = 5+7+9+11+..+105. E = 4+6+8+10+...+104
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-> SOLUTION: without computing each sum find which is greater o or e and by how much o = 5+7+9+11+..+105. E = 4+6+8+10+...+104
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Question 1163476: without computing each sum find which is greater o or e and by how much o = 5+7+9+11+..+105. E = 4+6+8+10+...+104 Found 2 solutions by solver91311, ikleyn:Answer by solver91311(24713) (Show Source):
In each sum there are exactly the same number of terms, namely 101 terms. Each term in sum O is one larger than the corresponding term in sum E. That should be enough information for you to answer the question on your own.
John
My calculator said it, I believe it, that settles it
Without computing, it is clear that the number of addends is the same in both sums.
From the other side, each addend in the first sum is 1 unit greater than the corresponding addend in the second sum.
It leads us to the conclusion that the O-value is greater than E-value.
Next, O-value is greater than E-value exactly by the number of addends in each sum.
The number of intervals of the length 2 between 4 and 104 inclusive is = = 50.
Hence the number of terms in each sum is 50+1 = 51.
Thus O-value is 51 units greater than E-value.
