Question 1163440:  Divide 56 into two parts such that three times the first part exceeds one third of the second by 48. The parts are
 
 
 Answer by math_helper(2461)      (Show Source): 
You can  put this solution on YOUR website!  
From the given information, you can formulate two equations 
x+y = 56 
  
3x = (1/3)y + 48 
 
 
These can be solved for x=20, y=36 
 
 
This is also a great problem to try to solve in your head, without using pencil and paper.   
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