SOLUTION: Please help me out: Integer whose square are less than 200 but greater than 40?

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Question 1163378: Please help me out: Integer whose square are less than 200 but greater than 40?
Found 3 solutions by math_helper, ikleyn, MathTherapy:
Answer by math_helper(2461)   (Show Source):
You can put this solution on YOUR website!

You can guess the solutions pretty easily:
not a solution
not a solution
is a solution
is a solution
...
etc.
Keep increasing the integer value until its square is 200 or higher.

Keep in mind the "integers" include the addititive inverses (negative numbers) and for n<0. Thus, -7, -8, etc. will also be in the set of solutions.

Answer by ikleyn(52847)   (Show Source):
You can put this solution on YOUR website!
.

To the list, presented by tutor @MathTherapy, add the numbers +/- 14.

Answer by MathTherapy(10555)   (Show Source):
You can put this solution on YOUR website!
Please help me out: Integer whose square are less than 200 but greater than 40?

Let INTEGERS be I
Then we get: 40 < I² < 200
< < ------ Taking square root of each component of compound inequality, while ADDING ±
< I <
Integers, or