SOLUTION: If 2 cars were 300 miles apart at 12 noon, and drove until they met each other at 3 pm, find the speeds of both cars. 1 car was driving at a speed of 10 mph faster then the other.
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: If 2 cars were 300 miles apart at 12 noon, and drove until they met each other at 3 pm, find the speeds of both cars. 1 car was driving at a speed of 10 mph faster then the other.
Log On
Question 1163242: If 2 cars were 300 miles apart at 12 noon, and drove until they met each other at 3 pm, find the speeds of both cars. 1 car was driving at a speed of 10 mph faster then the other. Answer by ikleyn(52775) (Show Source):
Let x be the rate of the slower car, in miles per hour;
then the rate of the faster car is (x+10) mph.
The total distance equation is then
3x + 3*(x+10) = 300 miles (the "3" here is "3 hours from 12 noon to 3 pm).
From the equation,
3x + 3x + 30 = 300
6x = 300 - 30 = 270
x = 270/6 = 45.
ANSWER. The slower car rate was 45 mph; the faster car 45+10 = 55 mph.
