Question 116310: 3 men go into a motel. The man behind the desk said the room is $30, so each man paid $10 and went to the room.
A while later, the man behind the desk realized the room was only $25, so he sent the bellboy to the 3 guys' room with $5. On the way the bellboy couldn't figure out how to split the $5 evenly between the 3 men, so he gave each man $1 and kept the other $2 for himself.
This meant that the 3 men each paid $9 for the room which is a total of $27; add the $2 that the bellboy kept = $29.
Where is the other dollar?
Found 2 solutions by josmiceli, ptaylor:
Answer by josmiceli(19441)   (Show Source):
You can put this solution on YOUR website! It should amount to the same thing if the 3 men selt one of them to
collect the $5 (assuming they knew what was going on) and give
the bellboy a $2 tip.
Then, They will have paid $30 - $3 = $27. If the bellboy gave the
tip back (not likely, but if he did) Then the 3 men will have been charged
$25 for the room as the desk man wanted. In other words,
the $2 gets subtracted from the $27, not added to it.
Answer by ptaylor(2198)  (Show Source):
You can put this solution on YOUR website! The supposition that the men paid $27 for their rooms is not correct. The men paid $25 for their rooms and that $25 is in the cash register. Each man got back $1 and the bellboy kept $2, so $25+$3+$2=$30 or we could look at it another
way:
3*$9=$27 (what they thought they were paying) minus the $2 kept by the bellboy=$25 (what they were actually paying)-- the amount in the cash register.
Actually, this problem has a very good moral to it: "As you go through life, you need to keep track of where the money is"
Hope this helps---ptaylor
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