SOLUTION: 1. A cabinet is pulled across a cemented floor with a rope that makes an angle of 40degrees with the floor. What is the component of the force parallel to the floor if 80-N force i
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Question 1163044: 1. A cabinet is pulled across a cemented floor with a rope that makes an angle of 40degrees with the floor. What is the component of the force parallel to the floor if 80-N force is exerted?
2. What is the height in centimeters of a person who is 5 feet 7 inches tall?
3. The wind blows toward 40 degrees with a velocity of 50km/h. What is the vertical component of the wind’s velocity?
4. Ruth walks 5 km North, then 4 km South and finally 3 km East. Find her final displacement.
5. A car travels from rest and attains a speed of 60 m/s in 20 seconds. How far has the car traveled in 20 sec?
(2) To solve problem (2), use the facts 1 foot = 12 inches; 1 inch = 2.54 cm.
(5) The distance "how far" = , where "a" is the acceleration a = = = 3 m/s^2.
Thus "how far" = = = 3*200 = 600 meters.
Interesting, that this distance is the same as if you multiply the average speed of 30 m/s by the time 20 seconds
"how far" = = 30 m/s * 20 s = 600 meters.
It is the same as "how far" = .
Memorize these formulas and the method of solution (!)
In the future, do not post more than 1 problem / question per post.
You can put this solution on YOUR website! 2. What is the height in centimeters of a person who is 5 feet 7 inches tall?
It's a conversion.
Look it up.
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3. The wind blows toward 40 degrees with a velocity of 50km/h. What is the vertical component of the wind’s velocity?
No vertical info is given.
Winds are North & South, and vertical. No vertical info is given.
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4. Ruth walks 5 km North, then 4 km South and finally 3 km East. Find her final displacement.
Use graph paper.
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5. A car travels from rest and attains a speed of 60 m/s in 20 seconds. How far has the car traveled in 20 sec?
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Assuming the acceleration is uniform, its average speed is 30 m/s
30*20 = 600 meters.
We should not have to make assumptions. It should be specified.