SOLUTION: I have to divide the two polynomials (21c^2-29c-18) divided by (3c-5). Thank you in advance.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I have to divide the two polynomials (21c^2-29c-18) divided by (3c-5). Thank you in advance.      Log On


   

Question 116302: I have to divide the two polynomials (21c^2-29c-18) divided by (3c-5). Thank you in advance.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The first term Is 7c because
%283c+-+5%29%2A7c+=+21c%5E2+-+35c when you subtract this from
21c%5E2+-+29c+-+18 you get 6c+-+18
The 2nd term is %2B2 because
%283c+-+5%29%2A2+=+6c+-+10 when you subtract this from
6c+-+18 you get -8 remainder
so, the answer is
7c+%2B+2+-+%288+%2F+%283c+-+5%29%29 answer
If you multiply this by 3c+-+5. you get
21c%5E2+-+29c+-+18