SOLUTION: You need a 20% acid solution. You have 980 mL of 15% on hand. How much of a 90% acid solution should you add to obtain the desired solution?

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Question 1162996: You need a 20% acid solution. You have 980 mL of 15% on hand. How much of a 90% acid solution should you add to obtain the desired solution?
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52864) About Me  (Show Source):
You can put this solution on YOUR website!
.

The base equation is


    0.9*x + 0.15*980 = 0.2*(x+980).


It states that the amounts of the pure acid in ingredients (left side) 
sum up to the amount of the pure acid in resulting mixture (right side).


From the equation,


    x = %280.2%2A980+-+0.15%2A980%29%2F%280.9-0.2%29 = 70 mL.


ANSWER.  70 mL of the 90% acid solution to add.

Solved.

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It is a standard and typical mixture problem.

In this site, there is a bunch of lessons,  covering various types of mixture problems.  See introductory lessons
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Word problems on mixtures for antifreeze solutions
    - Word problems on mixtures for alloys
    - Typical word problems on mixtures from the archive

Read them and become an expert in solution the mixture word problems.

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Mixture problems".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.



Answer by greenestamps(13206) About Me  (Show Source):
You can put this solution on YOUR website!


Here is an alternative to the standard algebraic solution method shown by the other tutor.

The 20% target is much closer to the 15% of the original solution than it is to the 90% of the solution that is being added. So the amount of 90% acid being added should be very small compared to the 980mL of the original solution.

Specifically, 20% is only 1/15 of the way from 15% to 90%. (15 to 90 is a difference of 75; 15 to 20 is a difference of 5; 5/75 = 1/15.)

That means 1/15 of the final mixture should be the 90% acid that is being added.

So the 980mL of the original 15% acid is 14/15 of the final mixture; that makes 1/15 of the final mixture 980/14 = 70mL.

ANSWER: 70mL of the 90% acid should be used.

CHECK:
.15(980)+.90(70) = 147+63 = 210
.20(980+70) = .20(1050) = 210