I'm going to presume you know how to rationalize your denominators if necessary, and please note that one of these two solutions is extraneous and must be discarded. I'll leave it to you to figure out which one.
John
My calculator said it, I believe it, that settles it
Two angles that have sum π/2 are complementary, thus the sine of one is the
cosine of the other and vice-versa. So a right triangle that contains such
a pair of complementary angles would be:
The angle with the red arc is arcsin(x) and the angle with the blue arc is
arcsin(2x).
By the Pythagorean theorem,
Since the triangle can be placed in any quadrant, we use ±.
Edwin