SOLUTION: The manager of a candy store wants to prepare 200 kg of a mixture for a halloween promotion to sell at $4.84 per kg. How much $4 per kg candy should be combined with $5.20 per kg c

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: The manager of a candy store wants to prepare 200 kg of a mixture for a halloween promotion to sell at $4.84 per kg. How much $4 per kg candy should be combined with $5.20 per kg c      Log On


   

Question 1162619: The manager of a candy store wants to prepare 200 kg of a mixture for a halloween promotion to sell at $4.84 per kg. How much $4 per kg candy should be combined with $5.20 per kg candy for the required mix?
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
This type done hundreds and hundreds of time.


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store wants to prepare 200 kg of a mixture for a halloween promotion to sell at $4.84 per kg. How much $4 per kg candy should be combined with $5.20 per kg candy for the required mix?
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..., store wants to prepare M kg of a mixture for a Halloween promotion to sell at $T per kg. How much $L per kg candy should be combined with $H per kg candy for the required mix?
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If the question is only for the amount of the cheaper priced candy to use, then
x for the cheap candy
M-x for the more expensive candy
Lx%2BH%28M-x%29=TM
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Lx%2BHM-Hx=TM
Lx-Hx=TM-HM
%28L-H%29x=M%28T-H%29
x=M%28%28T-H%29%2F%28L-H%29%29
highlight%28x=M%28%28H-T%29%2F%28H-L%29%29%29
You substitute your given values and evaluate.