SOLUTION: you have a bag containing 3 green marbles, 4 red marbles, and 2 yellow marbles. you select 1 marble randomly. what are the odds against selecting a green or yellow marble?
a. 5:4
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-> SOLUTION: you have a bag containing 3 green marbles, 4 red marbles, and 2 yellow marbles. you select 1 marble randomly. what are the odds against selecting a green or yellow marble?
a. 5:4
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Question 1162559: you have a bag containing 3 green marbles, 4 red marbles, and 2 yellow marbles. you select 1 marble randomly. what are the odds against selecting a green or yellow marble?
a. 5:4
b. 9:4
c.4:9
d.4:5
The goal is to get a green or yellow marble. There are 3 green and 2 yellow, making 3+2 = 5 total. So there are 5 ways to get what we want. There are 4 ways to get what we don't want (those four red marbles)
The odds in favor of getting green or yellow is 5:4. We simply list the number of ways to get what we want, followed by a colon, then the number of ways to get what we don't want.
We have this basic format
odds in favor = (want) : (dont want)
The odds against will be the complete opposite. We list what we dont want first, then what we want next
odds against = (dont want) : (want)
odds against = 4:5
(