SOLUTION: The value of a stock, A(x), over a year-long period decreased and then increased according to the quadratic function 𝐴(𝑥) = 0.75𝑥^2 − 6𝑥 + 20, where x represents the

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: The value of a stock, A(x), over a year-long period decreased and then increased according to the quadratic function 𝐴(𝑥) = 0.75𝑥^2 − 6𝑥 + 20, where x represents the       Log On


   

Question 1162512: The value of a stock, A(x), over a year-long period decreased and then increased according to the quadratic function 𝐴(𝑥) = 0.75𝑥^2 − 6𝑥 + 20, where x represents the number of months passed since you invested. The value of another stock, B(x), increased linearly according to the equation 𝐵(𝑥) = 2.75𝑥 + 1.50 over the same year. After how long are both stocks worth the same amount?
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


What don't you understand about this and what have you tried so far?


John

My calculator said it, I believe it, that settles it