Question 1162486: Assume that military aircraft use ejection seats designed for men weighing between 148.1 lb and 204 lb. If women's weights are normally distributed with a mean of 162.2 lb and a standard deviation of 46.8 lb, what percentage of women have weights that are within those limits? Are many women excluded with those specifications?
The percentage of women that have weights between those limits is
nothing%.
(Round to two decimal places as needed.)
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! z=(x-mean)/sd
so the first z is (148.1-162.2)/46.8 and the second is (204-162.2)/46.8, which are z s of -0.30 and 0.89 which is probability of 0.4312 or 43.12%
The calculator is nice for this 2nd VARS 2normalcdf ENTER (148.1,204,162.2,46.8) ENTER and probability of 0.4325 or 43.25%, the difference being rounding in the first. Many are excluded with these specifications.
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