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squareroot x+20-x=0
:
Without the use of brackets, it's rather ambiguous what is inside the radical;
I am assuming: - x = 0
:
Add x to both sides: = x
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Square both sides:
x + 20 = x^2
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Arrange as a quadratic on the right:
0 = x^2 - x - 20
:
This will factor to:
(x-5)(x+4) = 0
Solutions
x = +5
and
x = -4
:
Check solutions in original equation:
x=5 - 5 = 0 - 5 = 0
5 - 5 = 0
x=-4 -(-4) = 0
x=-4 + 4) = 0
4 + 4 does not = 0, not a solution
