SOLUTION: If a ball is thrown directly upward with a velocity of 40ft/sec, it’s height (in feet) after t seconds is given by h(t)=40t-16t^2. What is the maximum height attained by the ball

Algebra ->  Expressions-with-variables -> SOLUTION: If a ball is thrown directly upward with a velocity of 40ft/sec, it’s height (in feet) after t seconds is given by h(t)=40t-16t^2. What is the maximum height attained by the ball      Log On


   



Question 1162228: If a ball is thrown directly upward with a velocity of 40ft/sec, it’s height (in feet) after t seconds is given by h(t)=40t-16t^2. What is the maximum height attained by the ball
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
If a ball is thrown directly upward with a velocity of 40ft/sec, it’s [sic] height (in feet) after t seconds is given by h(t)=40t-16t^2. What is the maximum height attained by the ball
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It's the vertex of the parabola.
The vertex is at t = -b/2a
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it's = it is