Question 1162123: 1. 30 randomly selected students were asked how much TV they watched last night.
1, 3, 2, 0, 4, 1, 2, 1, 5, 3, 0, 4, 2, 3, 2, 3, 1, 0, 4, 5, 2, 1, 3, 3, 2, 4, 1, 5, 1, 0
a) What is single sample mean?
b) Average American teenager watches 4 hours with a standard deviation of 1.5. What is standard deviation of sample mean distribution?
2.Given that x has a Poisson distribution with μ = 5, what is the probability that x = 1?
3. You are a production manager for a newspaper. You want to find the percentage defective. Of 250 newspapers, 50 had defects. What is the 95% confidence interval estimate of the population proportion defective?
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! a. the sum is 68 and 68/30=2.27 hours
b. the sd is 1.5/sqrt(n) for a sample of n teenagers. The sample mean's point estimate would be 4 hours. I am assuming this is not relating to the above data. If it is, do a 1-var stats on the data
c. P(1)=e^(-5)*5^1/1!=5e^-5)=0.0337
d. p hat is 0.2 (50/250). The half-interval is z*sqrt (p*(1-p)/250)=sqrt (0.2*0.8/250)=1.96*0.0253=0.0496 rounding at end. The 95% CI is (0.15, 0.25) proportion of units defective.
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