SOLUTION: Find the total number of different 4-digit numbers using all the digits in the number 4129. Multiple choice answers: a. 24 b. 12 c. 18 d. 6

Algebra ->  Permutations -> SOLUTION: Find the total number of different 4-digit numbers using all the digits in the number 4129. Multiple choice answers: a. 24 b. 12 c. 18 d. 6      Log On


   



Question 1162098: Find the total number of different 4-digit numbers using all the digits in the number 4129.
Multiple choice answers:
a. 24
b. 12
c. 18
d. 6

Answer by ikleyn(52794) About Me  (Show Source):
You can put this solution on YOUR website!
.

It is the number of all permutations of four digits, which is 4*3*2*1 = 24.        ANSWER  


Another way to present it is to say that


    - any one of four digits can occupy the 1-st position;

    - any one of the remaining three digits can occupy the 2-nd position;

    - any one of the remaining two digits can occupy the 3-rd position;

    - and there is only one way to fill the last, 4-th position,


which gives you  4*3*2*1 options, in all.

Solved.

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On Permutations, see these introductory lessons
    - Introduction to Permutations
    - PROOF of the formula on the number of Permutations
    - Simple and simplest problems on permutations
    - Special type permutations problems
    - Problems on Permutations with restrictions
in this site.

Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic  "Combinatorics: Combinations and permutations".


Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.