SOLUTION: If there are 8 women and 4 men in a room and they put their names in a hat and then 3 names are selected at random, what is the probability of getting two men and one woman?
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Question 1162074: If there are 8 women and 4 men in a room and they put their names in a hat and then 3 names are selected at random, what is the probability of getting two men and one woman? Answer by ikleyn(52788) (Show Source):
The probability is P = (*).
The denominator of the formula is the number of all possible triples to form of 12 = 8 + 4 persons.
It is equal to = = 220.
The numerator of the formula (*) is the number to form the triples, formed of 1 woman and 2 men.
So, the answer is P = = = .
