SOLUTION: A stone is thrown directly upward from a height of 30 ft, with an initial velocity of 60 ft/sec. The height of the stone, in feet, t seconds after it has been thrown, is given by t
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Question 1162031: A stone is thrown directly upward from a height of 30 ft, with an initial velocity of 60 ft/sec. The height of the stone, in feet, t seconds after it has been thrown, is given by the function: s(t) = -16t^2 + 60t + 30.
Based on this model, what is the stone's maximum height? Also, how long does it take for the stone to reach its maximum height? Found 2 solutions by solver91311, Boreal:Answer by solver91311(24713) (Show Source):
The graph of is a parabola opening downward. The value of the function at the vertex is the maximum height and the value of the independent variable at the vertex is the time relative to the instant of launch for the projectile to reach maximum height.
has a vertex at the point
Use the coefficients from your given function to calculate the desired values.
John
My calculator said it, I believe it, that settles it
You can put this solution on YOUR website! h=-16t^2+60t+30
vertex is at t=-b/2a=-60/-32
a is the coefficient of the t^2 term or -16
b is the coefficient of the t term or 60
so -b/2a=-60/2(-16)
=60/32 seconds or 1.875 seconds
f(1.875)=86.25 feet
